> So, to match $foo's colour against $bar, I'd say
>
> $bar =~ /$foo.colour/;
No, you need the sub call parens as well:
$bar =~ /$foo.colour()/;
> Great, but how do I match $foo followed by any character followed by the
> literal "colour"?
$bar =~ /$foo.colour/;
> Would I have to use "\Q"?
No. You could use the $(...) scalar interpolator instead:
$bar =~ /$($foo).colour/;
> > > print "ok 5" unless ref ($a=(1,2,3))'
> ^^^^^^
Sorry, in my haste I missed that twist. You are, of course, correct.
> > > Oh, hrm. Shouldn't it be $a{test2}?
> > Yes. Or $a.{test}
>
> So "." isn't necessarily the "property" operator, then? OK.
> Time to spend more quality time with YACC. :(
Now there's an oxymoron, if ever I heard one. ;-)
Damian
