On Thu, Jun 07, 2001 at 06:37:26AM +1000, Damian Conway wrote:
> 
>    > So, to match $foo's colour against $bar, I'd say
>    > 
>    >     $bar =~ /$foo.colour/;
> 
> No, you need the sub call parens as well:
> 
>          $bar =~ /$foo.colour()/;

Hm, I thought Larry said you would need to use $() to interpolate
a method call. So this would be


          $bar =~ /$($foo.colour)/;

Graham.

Reply via email to