in http://archive.develooper.com/perl6-language%40perl.org/msg11451.html Larry Wall wrote: > for @cases ^| @newcases -> $x is rw | $y {...}
do I understand correctly that what happens is (more or less) -- any($a,$b) := any($x,$y) ? arcadi
in http://archive.develooper.com/perl6-language%40perl.org/msg11451.html Larry Wall wrote: > for @cases ^| @newcases -> $x is rw | $y {...}
do I understand correctly that what happens is (more or less) -- any($a,$b) := any($x,$y) ? arcadi