Erik Steven Harrison wrote:
--
On Wed, 12 Feb 2003 18:29:29
Joseph F. Ryan wrote:
As near as I can tell, the only problem with the nice flow of:
A I<literal> is a piece of data.
A I<scalar> is a variable that holds a literal.
A I<list> is a sequence of literals and scalars.
An I<array> is a variable that holds a list.
is the "Rvalue-assign list", which takes the form of:
($r1, $r2, $r3) = (1, 2, 3);
I don't see a problem here. The list on the right is still just
value, unmodifiable. It is a list of rvalues. When you use a variable
on the right hand side it is a rvalue. Similarly, a list of variables
doesn't flatten to it's values - it is the list itself that it is
immutable. It's individual members still retain asignibility in
rvalue context.
-Erik
Ah, I'm a compete fool. I meant Lvalue, not Rvalue. If you could do
a mental s:e/Rvalue/Lvalue on that last message, I would appreciate it.
Joseph F. Ryan
[EMAIL PROTECTED]
