--
On Thu, 13 Feb 2003 16:03:41
Joseph F. Ryan wrote:
>Erik Steven Harrison wrote:
>
>>
>>--
>>
>>On Wed, 12 Feb 2003 17:14:17
>> Erik Steven Harrison wrote:
>>
>>
>>>--
>>>
>>>On Wed, 12 Feb 2003 18:29:29
>>>Joseph F. Ryan wrote:
>>>
>>>
>>>>As near as I can tell, the only problem with the nice flow of:
>>>>
>>>>A I<literal> is a piece of data.
>>>>A I<scalar> is a variable that holds a literal.
>>>>
>>>>A I<list> is a sequence of literals and scalars.
>>>>An I<array> is a variable that holds a list.
>>>>
>>>>is the "Rvalue-assign list", which takes the form of:
>>>>
>>>>($r1, $r2, $r3) = (1, 2, 3);
>>>>
>>>>
>>>I don't see a problem here. The list on the right is still just
>>>value, unmodifiable. It is a list of rvalues. When you use a variable
>>>on the right hand side it is a rvalue. Similarly, a list of variables
>>>doesn't flatten to it's values - it is the list itself that it is
>>>immutable. It's individual members still retain asignibility in
>>>rvalue context.
>>>
>>>
>>
>>Okay, pardon me for replying to myself, but that was _really_ badly
>>worded. An example
>>
>>
>>foreach ($foo, $bar, $baz) {
>> .zoomdingle;
>>}
>>
>>The objects in the list retain full status qua objects even though
>>they are in a list, which is why we can call methods on them.
>>Similarly, the fact that a scalar variable acts as a value on the
>>lefthand side and a rvalue on the right hand side is retained even
>>though it is in a list. It is the list itself which is immutable.
>>Python programmers will grasp this real fast - it's just a tuple.
>>
>
>You're completely right. See my last message :-)
I *am*? Mark it on your calender!
-Erik
>
>
>Joseph F. Ryan
>[EMAIL PROTECTED]
>
>
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