On Thu, Apr 15, 2004 at 06:38:34PM -0400, Austin Hastings wrote: > The use of % as a modulo operator is purely a legacy from 'C', where it was > a failure: in 'C', the only number you care about for modulus is some power > of 2, and you get those using bitwise-and anyway.
I disagree with this completely. I've used % plenty of times in C for circular buffers that were not a powers of 2. % as modulus in C is NOT a failure. > If there is no comma-optional case, then you might even say: > > $foo % bar > $foo % $bar > > @foo @ 10 % bar (for some reason, I can't like @ as an array dereference. > [] does it for me.) I'd favor Juerd's proposal over this madness any day :) -Scott -- Jonathan Scott Duff Division of Nearshore Research [EMAIL PROTECTED] Senior Systems Analyst II
