Hi,
I'm trying to understand the following section in S03:
S03/"Junctive operators"
Junctions are specifically unordered. So if you say
for all(@foo) {...}
it indicates to the compiler that there is no coupling between loop
iterations and they can be run in any order or even in parallel.
Is this a "for" on a one element list, which happens to
be a junction, or does the all() flatten?
Is the whole block run once with 1,2 and 3, or does the
junction go into the block and autothread each operation?
for all(1,2,3) {
next if $_ < 2; # testing 1 or all(1,2,3) ?
%got{$_} = 1;
}
say %got.perl; # "(('2', 1), ('3', 1))" or "()" ?
The "no coupling" in s03 suggests to me that the right
answer is "(('2', 1), ('3', 1))", but I'm just guessing.
Brad
--
To ask when you already know is politeness. To ask when you don't know
is the rule. -- Hagakure http://bereft.net/hagakure/
