On Mon, May 09, 2005 at 02:08:31PM -0500, Patrick R. Michaud wrote: : Hmmm, then would $x.$j.2 then be equivalent to $x[$j-1][1] ?
Ouch. Larry
On Mon, May 09, 2005 at 02:08:31PM -0500, Patrick R. Michaud wrote: : Hmmm, then would $x.$j.2 then be equivalent to $x[$j-1][1] ?
Ouch. Larry