Larry Wall wrote:
You don't need to use | to store a capture any more than you need @ to
store an array. Just as
$x = @b;
gives you the original array,
Huh. I'm not used to this happening. So what would the following
code do, and why?
my @b = ('foo', 'bar');
my $x = @b;
$x = [EMAIL PROTECTED];
gives you the original array as well.
Err... don't you mean '@$x' instead of '@$a'?
: >we currently don't allow assignment to a capture, only binding.
: IOW, if you want someone to be able to say '$|x' and get '$a' as a
: result, you'd have to say '|x := \$a' (or perhaps '$|x := $a') instead
: of '|x = \$a'. Right?
Yes. That's how it's currently specced, anyway. (The \ is probably
required, or it'll try to bind to the contents of $a instead.)
There's some potential non-dwimmery here - either that, or there's a
steep learning curve (that I haven't mastered) before dwimmery can be
applied. I would expect $|x to refer to the scalar slot of the
capture object |x; as such, '$|x := ...' would mean 'bind the scalar
slot of |x to ...'. Likewise, I would expect '... := $a' to mean
'bind ... to the scalar variable $a'.
Or is the distinction between '$a' and 'the contents of $a' similar to
the distinction between a Unix filename and a Unix file ID? That is,
are we talking about the difference between hard links and symbolic
links in Unix?
Jonathan "Dataweaver" Lang
 I'm not sure that there's much of a difference between the two statements.