Hi everyone, This time using PDL 2.4.5
perldl> $a = zeroes(3,3); perldl> p $a [ [0 0 0] [0 0 0] [0 0 0] ] perldl> $a(1,1) = 1; perldl> p $a [ [0 0 0] [0 0 0] [0 0 0] ] perldl> $a(1,1)++; perldl> p $a [ [0 0 0] [0 1 0] [0 0 0] ] While I am surprised that the $a(1,1)++ syntax works but then I am also surprised that $a(1,1) = 1 does not do anything nor does it complain. Gabor _______________________________________________ Perldl mailing list [email protected] http://mailman.jach.hawaii.edu/mailman/listinfo/perldl
