Hi, This has to do with the inability to overload the '=' in perl. We therefore had to use a different operator for assignment into slices, '.='.
This is a well-known issue for newcomers to PDL but mentioned in the manuals. Try $a(1,1) .= 1 Christian On 12/11/2009, at 8:37 PM, Gabor Szabo wrote: > Hi everyone, > > This time using PDL 2.4.5 > > > perldl> $a = zeroes(3,3); > > perldl> p $a > > [ > [0 0 0] > [0 0 0] > [0 0 0] > ] > > perldl> $a(1,1) = 1; > > perldl> p $a > > [ > [0 0 0] > [0 0 0] > [0 0 0] > ] > > perldl> $a(1,1)++; > > perldl> p $a > > [ > [0 0 0] > [0 1 0] > [0 0 0] > ] > > > > While I am surprised that the $a(1,1)++ syntax works but then I am > also > surprised that $a(1,1) = 1 does not do anything nor does it complain. > > Gabor > > _______________________________________________ > Perldl mailing list > [email protected] > http://mailman.jach.hawaii.edu/mailman/listinfo/perldl -- Christian Soeller PhD Dept. of Physiology +64 9 3737599 x82770 University of Auckland Auckland, New Zealand fax +64 9 3737499 _______________________________________________ Perldl mailing list [email protected] http://mailman.jach.hawaii.edu/mailman/listinfo/perldl
