On 9/11/18 12:16 PM, Matthew Knepley wrote:
Gauss Runge-Kutta (including implicit midpoint) is symplectic and does not require any splitting.How do you talk about conservation of the symplectic form? The default model is on R^{2n} and you get 1 on one half and -1 on the other half. What do you mean no splitting?Matt
Matt, apply any method from above to R^N, N=2n; i.e., no splitting. Emil
