Thank you, that is very helpful information indeed! I will try it and send you 
my code when it works.

Best regards,
Yuyun
________________________________
From: Smith, Barry F. <[email protected]>
Sent: Saturday, February 15, 2020 10:02 PM
To: Yuyun Yang <[email protected]>
Cc: [email protected] <[email protected]>
Subject: Re: [petsc-users] Matrix-free method in PETSc

  Yuyun,

    If you are speaking about using a finite difference stencil on a structured 
grid where you provide the Jacobian vector products yourself by looping over 
the grid doing the stencil operation we unfortunately do not have exactly that 
kind of example.

    But it is actually not difficult. I suggest starting with 
src/ts/examples/tests/ex22.c It computes the sparse matrix explicitly with 
FormIJacobian()

    What you need to do is instead in main() use MatCreateShell() and 
MatShellSetOperation(,MATOP_MULT,(void (*)(void))MyMatMult) then provide the 
routine MyMatMult() to do your stencil based matrix free product; note that you 
can create this new routine by taking the structure of IFunction() and 
reorganizing it to do the Jacobian product instead. You will need to get the 
information about the shell matrix size on each process by calling 
DMDAGetCorners().

    You will then remove the explicit computation of the Jacobian, and also 
remove the Event stuff since you don't need it.

     Extending to 2 and 3d is straight forward.

     Any questions let us know.

   Barry

   If you like this would make a great merge request with your code to improve 
our examples.


> On Feb 15, 2020, at 9:42 PM, Yuyun Yang <[email protected]> wrote:
>
> Hello team,
>
> I wanted to apply the Krylov subspace method to a matrix-free implementation 
> of a stencil, such that the iterative method acts on the operation without 
> ever constructing the matrix explicitly (for example, when doing backward 
> Euler).
>
> I'm not sure whether there is already an example for that somewhere. If so, 
> could you point me to a relevant example?
>
> Thank you!
>
> Best regards,
> Yuyun

Reply via email to