Hi!
It worked.
Thank you very much.
Andrus.
13.02.2022 16:46 Torsten Förtsch kirjutas:
WITH x AS (
SELECT *
, sum(hours) OVER w AS s
FROM hours
WINDOW w AS (PARTITION BY person ORDER BY job_id)
)
SELECT *
, greatest(least(s, 120) - coalesce(lag(s, 1) OVER w, 0), 0) AS
regular
, hours - greatest(least(s, 120) - coalesce(lag(s, 1) OVER w, 0),
0) AS overtime
FROM x
WINDOW w AS (PARTITION BY person ORDER BY job_id)
On Sun, Feb 13, 2022 at 1:57 PM Andrus <kobrule...@hot.ee> wrote:
Hi!
Thank you. In this result, regular and overtime columns contain
running totals.
How to fix this so that those columns contain just hours for each job?
sum on regular column should not be greater than 120 per person.
sum of regular and overtime columns must be same as sum of hours
column in hours table for every person.
Andrus.
13.02.2022 14:46 Torsten Förtsch kirjutas:
something like
SELECT *
, least(sum(hours) OVER w, 120) AS regular
, greatest(sum(hours) OVER w - 120, 0) AS overtime
FROM hours
WINDOW w AS (PARTITION BY person ORDER BY job_id);
job_id | person | hours | regular | overtime
--------+--------+-------+---------+----------
2 | bill | 10 | 10 | 0
5 | bill | 40 | 50 | 0
8 | bill | 10 | 60 | 0
10 | bill | 70 | 120 | 10
11 | bill | 30 | 120 | 40
13 | bill | 40 | 120 | 80
15 | bill | 10 | 120 | 90
4 | hugo | 70 | 70 | 0
7 | hugo | 130 | 120 | 80
1 | john | 10 | 10 | 0
3 | john | 50 | 60 | 0
6 | john | 30 | 90 | 0
9 | john | 50 | 120 | 20
12 | john | 30 | 120 | 50
14 | john | 50 | 120 | 100
On Sun, Feb 13, 2022 at 12:47 PM Andrus <kobrule...@hot.ee> wrote:
Hi!
Hours table contains working hours for jobs:
create table hours (
jobid integer primary key, -- job done, unique for person
personid char(10) not null, -- person who did job
hours numeric(5,2) not null -- hours worked for job
)
Hours more than 120 are overtime hours.
How to split regular and overtime hours into different
columns using running total by job id and partition by person id?
For example, if John did 3 jobs 1, 2,3 with 90, 50 and 40
hours (total 180 hours) for each job correspondingly, result
table should be:
personid jobid normal_hours overtime_hours
john 1 90 0
john 2 30 20
john 3 0 40
sum on normal_hours column should not be greater than 120 per
person.
sum of normal_hours and overtime_hours columns must be same
as sum of hours column in hours table for every person.
Note that since hours running total becomes greater than 120
in job 2, job 2 hours should appear in both hours columns.
Maybe window functions can used.
Andrus.
