On 2023-02-13 18:33:34 +0900, Kyotaro Horiguchi wrote:
> At Mon, 13 Feb 2023 10:15:03 +0530, Bharath Rupireddy 
> <bharath.rupireddyforpostg...@gmail.com> wrote in 
> > On Sun, Feb 12, 2023 at 11:01 PM Andres Freund <and...@anarazel.de> wrote:
> > >
> > > On 2023-02-12 19:59:00 +0530, Bharath Rupireddy wrote:
> > > >       /* Prepare to write out a lot of copies of our zero buffer at 
> > > > once. */
> > > >       for (i = 0; i < lengthof(iov); ++i)
> > > >       {
> > > > -             iov[i].iov_base = zbuffer.data;
> > > > +             iov[i].iov_base = (void *) (unconstify(PGAlignedBlock *, 
> > > > &zbuffer)->data);
> > > >               iov[i].iov_len = zbuffer_sz;
> > > >       }
> > >
> > > Another thing: I think we should either avoid iterating over all the IOVs 
> > > if
> > > we don't need them, or, even better, initialize the array as a constant, 
> > > once.
> 
> FWIW, I tried to use the "{[start .. end] = {}}" trick (GNU extension?
> [*1]) for constant array initialization, but individual members don't
> accept assigning a const value, thus I did deconstify as the follows.
> 
> >     static const struct iovec       iov[PG_IOV_MAX] =
> >             {[0 ... PG_IOV_MAX - 1] =
> >              {
> >                      .iov_base = (void *)&zbuffer.data,
> >                      .iov_len = BLCKSZ
> >              }
> >             };
> 
> I didn't checked the actual mapping, but if I tried an assignment
> "iov[0].iov_base = NULL", it failed as "assignment of member
> ‘iov_base’ in read-only object", so is it successfully placed in a
> read-only segment?
> 
> Later code assigns iov[0].iov_len thus we need to provide a separate
> iov non-const variable, or can we use pwrite instead there?  (I didn't
> find pg_pwrite_with_retry(), though)

Given that we need to do that, and given that we already need to loop to
handle writes that are longer than PG_IOV_MAX * BLCKSZ, it's probably not
worth avoiding iov initialization.

But I think it's worth limiting the initialization to blocks.

I'd also try to combine the first pg_writev_* with the second one.

Greetings,

Andres Freund


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