Robert Haas <[email protected]> writes:
> On Fri, Jul 30, 2010 at 1:13 AM, Tom Lane <[email protected]> wrote:
>> Perhaps, but I think you're confused on at least one point.
>> numeric(2,1) has to be able to hold 2 decimal digits, not 2
>> NumericDigits (which'd actually be 8 decimal digits given
>> the current code).
> I get that. The point is: if one of those 2 decimal digits is before
> the decimal point and the other is after it, then two NumericDigits
> will be used.
Ah, I see. Maybe we should allow for one more NumericDigit in the
calculation for such cases. I guess you could look at the scale too
to detect if the case is possible, but not sure it's worth the trouble.
regards, tom lane
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