On Mon, May 8, 2017 at 10:12 PM, Tom Lane <[email protected]> wrote:
> Simon Riggs <[email protected]> writes:
>> So rearranged code a little to keep it lean.
>
> Didn't you break it with that?  As it now stands, the memcpy will
> copy the nonzero value.
>

Right, I'd missed it. That code should be placed before first memcpy.

Regards,

--
Masahiko Sawada
NIPPON TELEGRAPH AND TELEPHONE CORPORATION
NTT Open Source Software Center


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