Jeff Davis <[EMAIL PROTECTED]> writes:
> On Wed, 2007-05-30 at 15:56 -0400, Tom Lane wrote:
>> In the sync-scan case the idea seems pretty bogus anyway, because the
>> actual working set will be N backends' rings not just one.

> I don't follow. Ideally, in the sync-scan case, the sets of buffers in
> the ring of different scans on the same relation will overlap
> completely, right?

> We might not be at the ideal, but the sets of buffers in the rings
> shouldn't be disjoint, should they?

According to Heikki's explanation here
each backend doing a heapscan would collect its own ring of buffers.
You might have a few backends that are always followers, never leaders,
and so never actually fetch any pages --- but for each backend that
actually did any I/O there would be a separate ring.  In practice I'd
expect the lead would "change hands" pretty often and so you'd see all
the backends accumulating their own rings.

                        regards, tom lane

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