Thank you all kindly response..... : ) I am currently using postgres 7.3, so any example or solution for version after 7.4 if i want to create an index with substr function???
Thanks, Ray ----- Original Message ----- From: "Stephan Szabo" <[EMAIL PROTECTED]> To: "Ray" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Thursday, October 21, 2004 10:57 AM Subject: Re: [PERFORM] create index with substr function > > On Thu, 21 Oct 2004, Ray wrote: > > > Hi All, > > > > I have a table in my postgres: > > Table: doc > > Column | Type | Modifiers > > ---------------+-----------------------------+----------- > > doc_id | bigint | not null > > comp_grp_id | bigint | not null > > doc_type | character varying(10)| not null > > doc_urn | character varying(20)| not null > > > > I want to create an index on doc_urn column with using substr function like this: > > CREATE INDEX idx_doc_substr_doc_urn ON doc USING btree (SUBSTR(doc_urn,10)); > > > > but there is an error: > > > > ERROR: parser: parse error at or near "10" at character 68 > > > > what's wrong for this SQL? As I have found some reference on the > > internet, I can't find anything wrong in this SQL. > > What version are you using? If you're using anything previous to 7.4 then > the above definately won't work and the only work around I know of is to > make another function which takes only the column argument and calls > substr with the 10 constant. > ---------------------------(end of broadcast)--------------------------- TIP 1: subscribe and unsubscribe commands go to [EMAIL PROTECTED]