Tom Lane wrote: > Bruce Momjian <[EMAIL PROTECTED]> writes: > >>> select nextval('temp_counter'), * from (select .... order by ...); > >> > >> Approximately the same solution, but without saving the result in a temp > >> table. > > > I thought about doing it this way. However, a subselect as a > > pseudotable is not guaranteed to return the data in any specific order, > > so I don't think this method work work reliably. > > Say what? Given the ORDER BY in the subselect, it will. > > Of course, you can't do any grouping or other processing at the outer > level, but the example as given is just fine.
When you specify a table in FROM, there is no ordering to the table. Is it guaranteed that a subquery in FROM _does_ have an ordering. Does ANSI say it has an ordering? What if the subquery is involved in a join? -- Bruce Momjian | http://candle.pha.pa.us [EMAIL PROTECTED] | (610) 359-1001 + If your life is a hard drive, | 13 Roberts Road + Christ can be your backup. | Newtown Square, Pennsylvania 19073 ---------------------------(end of broadcast)--------------------------- TIP 2: you can get off all lists at once with the unregister command (send "unregister YourEmailAddressHere" to [EMAIL PROTECTED])