Julien Cigar wrote:
What I would like is a query that returns all the specimen_id of
this table which have _all_ the given test_bit_id.
[snip]
With the following I got a syntax error:
select specimen_id
from specimen_test_bits
where test_bit_id = all(1,2,3,4);
It's expecting an array here. You'd have to write
= all('{1,2,3,4}')
But that would have the same problem as...
The following works but no rows are returned :
select specimen_id
from specimen_test_bits
where test_bit_id = all(select id from test_bits where id in (1,2,3,4));
It's testing each row individually and of course one row can't match ALL
four values.
What you want to do is count the distinct values. Something like:
SELECT
specimen_id
FROM foo
GROUP BY
specimen_id
HAVING
count(distinct test_bit_id) = 4
;
--
Richard Huxton
Archonet Ltd
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TIP 6: explain analyze is your friend
