Thanks :) it works as expected 

Julien

On Wed, 2007-11-14 at 14:31 +0100, hubert depesz lubaczewski wrote:
> On Wed, Nov 14, 2007 at 02:39:02PM +0100, Julien Cigar wrote:
> > With the following I got a syntax error:
> > select specimen_id 
> > from specimen_test_bits 
> > where test_bit_id = all(1,2,3,4);
> 
> where test_bit_id in (1,2,3,4)
> group by specimen_id
> having count(distinct test_bit_id) = 4;
> 
> depesz
> 


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