Not tested.
1. select count(t2.activity_id),
t1.activity_id
from (select distinct activity_id from foo_activity) as t1, -- assumes
all activities exist somewhere in table
left join foo_activity t2 on (t1.activity_id = t2.activity_id)
WHERE created >= '01/01/2011' and created < '01/08/2011'
group by 2
order by 2;
2. -- use generate_series for simple numbering scheme
select count(t2.activity_id)
t1.x as 'activity_id"
from generate_series(1,12) as t1(x),
left join foo_activity t2 on (t1.x = t2.activity_id)
WHERE created >= '01/01/2011' and created < '01/08/2011'
group by 2
order by 2;
On Fri, Feb 11, 2011 at 1:46 PM, Aaron Burnett <aburn...@bzzagent.com>wrote:
>
> Hi,
>
> I'm just drawing a blank entirely today and would appreciate some help on
> this.
>
> The long and short; there are 12 distinct activities that need to be
> queried
> on a weekly basis:
>
> SELECT count(activity_id), activity_id
> FROM foo_activity
> WHERE created >= '01/01/2011' and created < '01/08/2011'
> GROUP BY 2
> ORDER BY 2;
>
> It gives me this answer, which is correct:
>
> count | activity_id
> -------+---------------------
> 1502 | 1
> 11 | 2
> 2 | 3
> 815 | 4
> 4331 | 7
> 30 | 9
> 1950 | 10
> 7 | 11
> 67 | 12
>
> But what I need to see is if there are no activities for the particular
> activity_id that week, that it lists the count as 0 and lists the
> activity_id associated like this:
>
> count | activity_id
> -------+---------------------
> 1502 | 1
> 11 | 2
> 2 | 3
> 815 | 4
> 0 | 5
> 0 | 6
> 4331 | 7
> 0 | 8
> 30 | 9
> 1950 | 10
> 7 | 11
> 67 | 12
>
> Thanking you in advance for any help on this. The caffiene seems to be not
> working well today.
>
> Aaron
>
>
> --
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>
--
Peter Steinheuser
psteinheu...@myyearbook.com
