Assuming you have a table which lists all possible activities, with one activity per row and no duplicates, you need to do a left outer join between activities and your query result. That will generate a resultset that has at least one row for every row in activities, with nulls in all the columns coming from the query for rows that don't have a match. Then use coalesce to turn null into 0. Something like this:
select a.activity_id, coalesce(q.total, 0) as total from activities a left outer join (select fa.activity_id, count(fa.activity_id) as total from foo_activity fa where fa.created between '01/01/2011' and '01/08/2011' group by 1) q on a.activity_id = q.activity_id order by a.activity_id If you don't have an activities table with one row per activity, just replace the activities table in that query with another query - select distinct activity_id from foo_activity On Fri, Feb 11, 2011 at 10:46 AM, Aaron Burnett <aburn...@bzzagent.com>wrote: > > Hi, > > I'm just drawing a blank entirely today and would appreciate some help on > this. > > The long and short; there are 12 distinct activities that need to be > queried > on a weekly basis: > > SELECT count(activity_id), activity_id > FROM foo_activity > WHERE created >= '01/01/2011' and created < '01/08/2011' > GROUP BY 2 > ORDER BY 2; > > It gives me this answer, which is correct: > > count | activity_id > -------+--------------------- > 1502 | 1 > 11 | 2 > 2 | 3 > 815 | 4 > 4331 | 7 > 30 | 9 > 1950 | 10 > 7 | 11 > 67 | 12 > > But what I need to see is if there are no activities for the particular > activity_id that week, that it lists the count as 0 and lists the > activity_id associated like this: > > count | activity_id > -------+--------------------- > 1502 | 1 > 11 | 2 > 2 | 3 > 815 | 4 > 0 | 5 > 0 | 6 > 4331 | 7 > 0 | 8 > 30 | 9 > 1950 | 10 > 7 | 11 > 67 | 12 > > Thanking you in advance for any help on this. The caffiene seems to be not > working well today. > > Aaron > > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql >
