ID:               21912
 Updated by:       [EMAIL PROTECTED]
 Reported By:      [EMAIL PROTECTED]
-Status:           Open
+Status:           Verified
-Bug Type:         Unknown/Other Function
+Bug Type:         GetImageSize related
 Operating System: Linux
-PHP Version:      4.3.0
+PHP Version:      4.3.1-dev
 New Comment:

I can reproduce this with latest stable CVS (4.3.1-dev)
It does work if the image is local..but not if it's remote.



Previous Comments:
------------------------------------------------------------------------

[2003-01-27 16:12:37] [EMAIL PROTECTED]

Hallo,

I have a weird problem, which I think is a bug. The following script
works with PHP 4.1.2 (I know, very outdated), but DOES NOT work with
PHP 4.3.0:

<?
error_reporting (E_ALL);

$foto="http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg";;
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");

print ("<p>\n");

$foto="http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg";;
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");
?>

The problem is :

The first image works fine, it shows the height, width and type.
However, the information about the second image is only beeing
displayed if using PHP 4.1.2. With PHP 4.3.0 no information is beeing
displayed.


------------------------------------------------------------------------


-- 
Edit this bug report at http://bugs.php.net/?id=21912&edit=1

Reply via email to