#21912 [Ver]: getimagesize() on remote images fails sometimes..

[helly]

 ID:               21912
 Updated by:       [EMAIL PROTECTED]
 Reported By:      [EMAIL PROTECTED]
 Status:           Verified
 Bug Type:         GetImageSize related
 Operating System: Linux
 PHP Version:      4.3.1-dev
 New Comment:

I suppose ther is another problem :-)

When i download the image and put it on one of my local servers it
works:

[marcus@zaphod php4-HEAD]$ php -r 'print_r(getimagesize($argv[1]));' --
http://zaphod.boerger.de/php/ext/exif/test/bug21912.jpg
Array
(
    [0] => 389
    [1] => 500
    [2] => 2
    [3] => width="389" height="500"
    [bits] => 8
    [channels] => 3
    [mime] => image/jpeg
)
[marcus@zaphod php4-HEAD]$ php -r 'var_dump(getimagesize($argv[1]));'
-- http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg
bool(false)


Previous Comments:
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[2003-01-28 13:52:36] [EMAIL PROTECTED]

Yes, it has indeed something to do with the image. If I take another
image it works fine! But there must be some difference in the PHP
versions since the 2nd pictures only works with PHP 4.1.2, and not with
the latest PHP version.

------------------------------------------------------------------------

[2003-01-28 13:26:00] [EMAIL PROTECTED]

php -r '$size =
getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg";);
print_r($size); echo "\n";'

works without problems here (PHP 4.3.0), while

php -r '$size =
getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg";);
print_r($size); echo "\n";'

prints nothing. ImageMagick's "identify" sees some strange ipct data in
the second image; probably these make getimagesize() misbehave.

------------------------------------------------------------------------

[2003-01-27 17:25:35] [EMAIL PROTECTED]

I can reproduce this with latest stable CVS (4.3.1-dev)
It does work if the image is local..but not if it's remote.


------------------------------------------------------------------------

[2003-01-27 16:12:37] [EMAIL PROTECTED]

Hallo,

I have a weird problem, which I think is a bug. The following script
works with PHP 4.1.2 (I know, very outdated), but DOES NOT work with
PHP 4.3.0:

<?
error_reporting (E_ALL);

$foto="http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg";;
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");

print ("<p>\n");

$foto="http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg";;
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");
?>

The problem is :

The first image works fine, it shows the height, width and type.
However, the information about the second image is only beeing
displayed if using PHP 4.1.2. With PHP 4.3.0 no information is beeing
displayed.


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Edit this bug report at http://bugs.php.net/?id=21912&edit=1