No, two is a more accurate comparison.
!==
Although for most cases != is sufficient.

""Richard S. Crawford"" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> use just one = sign.  So,
>
> if ($PASS != $PASSNOG) {...
>
>
> At 01:41 AM 3/15/01 +0100, Duky wrote:
> >Hmm.. maybe I wasn't clear enough... what I want is to check is WHEN the
> >two passwords aren't the same, then it should echo "password doesn't
> >match!". So when NOT the same, then echo. What to use for the NOT??
> >should it then be something like this with the exlamationmark?
> >
> >     if ($PASS !== $PASSNOG) {
> >        echo "password doesn't match! $back";
> >        exit;
> >        }
> >
> >
> >Duky
> >
> >
> >Duky wrote:
> > >
> > > Can somebody tell me what the proper statement is for this? I want two
> > > variables to match with eachother but this doesn't seems to work. Help
> > > please? THNX
> > >
> > >    if ($PASS != $PASSNOG) {
> > >       echo "password doesn't match! $back";
> > >       exit;
> > >       }
> > >
> > > Duky
> > >
> > > --
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