or you can put yuou r values into an array then for(loop) thru the thing
checking as you go.
Example ====>>>>
$img[] = "episodeID_a.jpg";
$img[] = "episodeID_b.jpg";
$img[] = "episodeID_c.jpg";
for ($x=1; $x <count($img); $x++) {
if (!$file_exists(.//$img[$x])) {
//Change the variable $img? and give it the value of a temporary, blank
image
echo "blank.jpg";
// more code
}else{
echo $img[$x];
// more code
}//end if
}//end for loop
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of Russ
Michell
Sent: Tuesday, March 27, 2001 10:46 AM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] A question - ($file_exists)
Hi there: What about doing it like this:
<?php
$num = mysql_num_rows($result);
while($row = mysql_fetch_array($result)) {
$image = $row['image'];
}
//Loop through all images in DB:
for($count = 0; $count < count($image); $count++) {
$display_this = $display_this . $image;
}
//end for-loop
}
//end-while loop
if($num != 0) {
//Images exist so display them:
echo $display_this;
}
else {
//Images don't exist so display blank inage:
echo "path/to/blank.gif;"
}
?>
#-------------------------------------------------------#
"Believe nothing - consider everything"
Russ Michell
Anglia Polytechnic University Webteam
http://gertrude.sipu.anglia.ac.uk/webteam
[EMAIL PROTECTED]
+44 (0)1223 363271 ext 2331
www.theruss.com
#-------------------------------------------------------#
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