** Reply to note from Jonathan Hilgeman <[EMAIL PROTECTED]> Fri, 22 Jun 2001 14:44:57
-0700
Jonathan asks:
> Whats your query look like? Do you perform any joins?
$query = "SELECT * FROM $table WHERE CustNo='$CustNo'";
Pretty vanilla stuff.
[ . . . ]
> BUT! If the field is NULL, php spits out this:
>
> "Warning: Undefined index: Website in
> f:\website\pmaco\admin\contacts1.php on line 241"
The offending line was:
if ($row["Website"]) {
// do stuff
}
and is now:
if (!is_null($row["Website"])) {
if (strlen($row["Website"])) {
// do stuff
}
}
Same warning msg. But if I substitute a numberic index, as in:
if ($row[33]) {
// do stuff
}
it works fine. But I need to use the associative index.
Regards,
Al S.
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