Maybe this helps:

$file = "/tmp/pathtoimage/image.jg"
$fp = fopen($file, filesize($file));
$image = fread($fp, filesize($file)); //not sure about fread function┐

print $image //or imagejpeg($image), I'm not sure..

Grtz,

Luc

[EMAIL PROTECTED]
----- Original Message -----
From: "Mark Gordon" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, July 29, 2001 10:31 PM
Subject: [PHP-DB] Still trying to get image from /tmp path


> Thanks, David.  That helped a little but now what I get is:
> <img src=/tmp/phpMVWr5Z> in the output.
>
> The tmp folder is up the directory tree outside of my www folder (on my
> web host's 'puter)- I don't have direct access to it.
>
> Heres the modified code:
>
>   $sql=mysql_query("SELECT bin_data FROM binary_data WHERE id=4");
>   $row = mysql_fetch_array($sql);
>   header("Content-type: image/jpeg");
>   echo "<img src=$row[0]>";
>
> How can I use the path stored in the db to retrieve the image?
>
> =====
> Mark
> [EMAIL PROTECTED]
>
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