The solution is easier than you think. You'll need to insert an if
statement in your option html tag that says
echo "<option VALUE=\"Signal Hill\">Signal Hill\n";
should become:
echo "<option VALUE=\"Signal Hill\"";
if ($store == 'Signal Hill') { print " selected"; }
echo ">Signal Hill</option>\n";
Jeff Grossman wrote:
>Hello,
>Here is the code I have:
>
>while ($row=mysql_fetch_array($result)) {
> $store=$row["store"];
> $jobdesc=$row["jobdesc"];
>echo "<FORM METHOD=post ACTION=update.php>";
>echo "<P>Store:
> <Select NAME=\"$store\">
> <option VALUE=\"Signal Hill\">Signal Hill
> <option VALUE=\"Reseda\">Reseda
> <option VALUE=\"Orange\">Orange
> <option VALUE=\"West Covina\">West Covina
> <option VALUE=\"Riverside\">Riverside
> <option VALUE=\"Norwalk\">Norwalk
> <option VALUE=\"Fountain Valley\">Fountain Valley
> <option VALUE=\"Pasadena\">Pasadena
> <option VALUE=\"Redondo Beach\">Redondo Beach
> <option VALUE=\"San Bernardino\">San Bernardino
> <option VALUE=\"Kearny Mesa\">Kearny Mesa
> <option VALUE=\"San Marcos\">San Marcos
> <option VALUE=\"Chino\">Chino
> <option VALUE=\"Coporate Office\">Corporate Office
> </select></P>";
>echo "<P><INPUT TYPE=text SIZE=35 NAME=\"Jobdesc\"
>VALUE=\"$jobdesc\"></P>";
>echo "<p><INPUT TYPE=submit VALUE=\"submit\" LABEL=\"Save
>Changes\"></P>";
>}
>
>
>Is want I am trying to do possible? I want the value which is stored in
>$store to automatically fill in on the drop down list. But, for some
>reason it is defaulting to the first option, and not using the value
>that is in the database.
>
>Can I use a drop down menu, or should I just go to radio buttons?
>
>Thanks,
>Jeff
>
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