<?php //.../... first part of the code is to connect to the right DB on a MySQL server. It works fine
//This code to show the query. It runs well under MySQL and gives 1 result : $query="SELECT Login, Password FROM `user` WHERE user.login=''$login'' and user.password=''$password''"; //This var should contain a query result ressource: $result_query=mysql_query($query); //Here's my error message after executing: // Supplied argument is not a valid MySQL result resource in this line: $result_table=mysql_fetch_array($result_query); // I thought that this var ($result_table) should contain the row of 2 cells //And I expected to read $result_table['login'] or $result_table[0] as the first cell of the row... // I any of you can help me, poor php newby... :o) Great thanks !! ?> -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
