$query="select * from my_contacts where contactid like '$cir'";
Kevin Ruiz wrote:
> I'm working on an application that selects a user's userid if their password
> and login match. If the login and password match I want my variable $cir to
> run its own select statement and return its corresponding contactid...for
> this example we'll say that value = 5. I then want to plug in $cir into my
> select statement that will show the user the list of his/her contacts and
> only theirs. This seems to be the select statement that's giving my
> $query = "select * from my_contacts where
> Whenever I run my script I get an error saying that I have a problem with my
> sql syntax. I know that the problem is with the variable becuase it runs
> fine with a value in it.
> I've tried writing the $cir as '$cir' and '\$cir' but nothing seems to work.
> Can anyone help.
> Thanks in advance
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