$result = mysql_query("select distinct country from search");
Janet
----- Original Message -----
From: "Chris Payne" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, January 16, 2002 1:29 PM
Subject: [PHP-DB] Unique Results?
Hi there everyone,
(Sorry if you got this twice, I don't think my mail server posted it
earlier).
I use the following code to populate a dropdown box from a MySQL database:
$db = mysql_connect("localhost","^^^","^^^");
mysql_select_db("mydb",$db);
$result = mysql_query("select country from search");
if ($result)
{
echo "<SELECT NAME='country'>";
while ($myrow = mysql_fetch_array($result))
{
echo "<OPTION VALUE=\"".$myrow["country"]."\">".
$myrow["country"]." </OPTION> ";
}
echo "</SELECT>";
}
However, this database has multiple country names the same (Aswell as unique
ones) how can I display just ONE of each entry? IE: say there are 5 africa,
3 britain etc ..... I only want the list to show 1 of each and not 5 and 3
and so on - how is this possible? Please help :-)
And thank you to everyone who helped me with an earlier enquiry, it's very
appreciated :-)
Chris Payne
www.planetoxygene.com
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