Your problem is that you've included the value of $park in single-quotes.
Therefore, because it contains NULL, i.e., \0, this is translated to '0' in
the INSERT statement. You must make your test prior to the INSERT statement
and use the proper $park value.
Or, you can:
if ($park == 'false'){
$park = NULL;
}
else{
$park = "\"$park\"";
};
in you INSERT statement change: '$park', to $park,
-----Original Message-----
From: Andy [mailto:[EMAIL PROTECTED]]
Sent: Friday, February 01, 2002 9:43 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Inserting NULL values does not work
Hi guys,
I am trying to insert a NULL value into a DB field. The value is not always
NULL so the statement is given. Unfortunatelly it is inserting 0 instead of
NULL.
How can I get the thing going with NULL???
Here is the code I am using:
if ($park == 'false'){
$park = NULL;
}
$stmt = "INSERT INTO $T1
(
belongs_to,
name,
caption,
country,
province,
city,
glacier,
park,
lake,
mountain,
beach,
comment,
keywords,
date_taken,
date_posted
)
VALUES
(
'$user_id',
'$picture',
'$caption',
'$country',
'$province',
'$city',
'$glacier',
'$park',
'$lake',
'$mountain',
'$beach',
'$comment',
'$keyword',
'$date_taken',
'$date_posted'
)";
Cheers Andy
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