Hello all, I'm very new to php and have been beating my head on the wall over this for 2 days. I've searched through the php documentation but I guess I either don't know where or what to look for or don't understand what I'm seeing. I think this has to be an array but the original doesn't seem to think so.(see below) I've tried ($myrow = mysql_fetch_array($result)) and still get the same errors. The original that I used as an example works OK showing the results of Name, Position. They didn't include a data cell for $myrow[3] ........... ========================================================= THIS WORKS: <?php
$title = "Welcome to the Web-Site of"; /*I commented this out and finaly removed it cuz I don't want the title echoed in the final page.*/ include("header.inc"); $result = mysql_query("SELECT * FROM employees",$db); echo "<table border=1>\n"; echo "<tr><td>Name</td><td>Position</tr>\n"; while ($myrow = mysql_fetch_row($result)) { echo("<tr><td>%s %s</td><td>%s</tr>\n", $myrow[1], $myrow[2], $myrow[3]); } echo "</table>\n"; include("footer.inc"); ?> =========================================================== What I am trying to do is to return the results of the query into a table with these items: +-----------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+----------------+ | id | tinyint(4) | | PRI | NULL | auto_increment | | year | int(4) | YES | | NULL | | | make | varchar(20) | YES | | NULL | | | model | varchar(20) | YES | | NULL | | | engine | varchar(20) | YES | | NULL | | | fuel | varchar(8) | YES | | NULL | | | trans | varchar(10) | YES | | NULL | | | condition | varchar(20) | YES | | NULL | | | price | varchar(10) | YES | | 0 | | | location | varchar(20) | YES | | NULL | | +-----------+-------------+------+-----+---------+----------------+ These are the errors that show up when I run the page in the browser. The database is local and I'm on Linux-Mandrake 8.1 using Apache web server. I can get the results I want from the command line, that is I can make queries and get the proper info returned. what have I done to cause it not to work? Warning: Supplied argument is not a valid MySQL-Link resource in /var/www/html/list.php3 on line 26 Warning: Supplied argument is not a valid MySQL result resource in /var/www/html/list.php3 on line 32 THIS DOESN'T: I get the table and the item name e.g. Year, Make etc. Once I get the 3 cells returning the proper info, I want to add the rest of the cells needed to display all the info in the web page. I don't think it should be a problem, comments on this? <?php include("header.inc"); //(Line 26 below, everything above "<?php" is plain html.) $result = mysql_query("SELECT * FROM autos",$db); echo "<table border=1>\n"; echo "<tr><td>Year</td><td>Make</td><td>Model</td></tr>\n"; //(Line 32 below) while ($myrow = mysql_fetch_row($result)) { //What does the '%s' mean? I read it someplace in the tutorial //but can't find it now. printf("<tr><td>%s %s</td><td>%s</tr>\n", $myrow[1], $myrow[2], $myrow[3]); } echo "</table>\n"; include("footer.inc"); ?> -- Ken Thompson, North West Antique Autos Payette, Idaho Email: [EMAIL PROTECTED] http://www.nwaa.com Sales and brokering of antique autos and parts. Linux- Coming Soon To A Desktop Near You Registered Linux User #183936 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php