Hello all,
I'm very new to php and have been beating my head on the wall over this for 2
days. I've searched through the php documentation but I guess I either don't
know where or what to look for or don't understand what I'm seeing.
I think this has to be an array but the original doesn't seem to think
so.(see below)
I've tried ($myrow = mysql_fetch_array($result)) and still get the same
errors.
The original that I used as an example works OK showing the results of Name,
Position. They didn't include a data cell for $myrow[3] ...........
=========================================================
THIS WORKS:
<?php
$title = "Welcome to the Web-Site of"; /*I commented this out and finaly
removed it cuz I don't want the title echoed in the final page.*/
include("header.inc");
$result = mysql_query("SELECT * FROM employees",$db);
echo "<table border=1>\n";
echo "<tr><td>Name</td><td>Position</tr>\n";
while ($myrow = mysql_fetch_row($result)) {
echo("<tr><td>%s %s</td><td>%s</tr>\n", $myrow[1], $myrow[2],
$myrow[3]);
}
echo "</table>\n";
include("footer.inc");
?>
===========================================================
What I am trying to do is to return the results of the query into a table
with these items:
+-----------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+----------------+
| id | tinyint(4) | | PRI | NULL | auto_increment |
| year | int(4) | YES | | NULL | |
| make | varchar(20) | YES | | NULL | |
| model | varchar(20) | YES | | NULL | |
| engine | varchar(20) | YES | | NULL | |
| fuel | varchar(8) | YES | | NULL | |
| trans | varchar(10) | YES | | NULL | |
| condition | varchar(20) | YES | | NULL | |
| price | varchar(10) | YES | | 0 | |
| location | varchar(20) | YES | | NULL | |
+-----------+-------------+------+-----+---------+----------------+
These are the errors that show up when I run the page in the browser.
The database is local and I'm on Linux-Mandrake 8.1 using Apache web server.
I can get the results I want from the command line, that is I can make
queries and get the proper info returned.
what have I done to cause it not to work?
Warning: Supplied argument is not a valid MySQL-Link
resource in /var/www/html/list.php3 on line 26
Warning: Supplied argument is not a valid MySQL result
resource in /var/www/html/list.php3 on line 32
THIS DOESN'T:
I get the table and the item name e.g. Year, Make etc.
Once I get the 3 cells returning the proper info, I want to add the rest of
the cells needed to display all the info in the web page. I don't think it
should be a problem, comments on this?
<?php
include("header.inc");
//(Line 26 below, everything above "<?php" is plain html.)
$result = mysql_query("SELECT * FROM autos",$db);
echo "<table border=1>\n";
echo "<tr><td>Year</td><td>Make</td><td>Model</td></tr>\n";
//(Line 32 below)
while ($myrow = mysql_fetch_row($result)) {
//What does the '%s' mean? I read it someplace in the tutorial
//but can't find it now.
printf("<tr><td>%s %s</td><td>%s</tr>\n", $myrow[1], $myrow[2],
$myrow[3]);
}
echo "</table>\n";
include("footer.inc");
?>
--
Ken Thompson, North West Antique Autos
Payette, Idaho
Email: [EMAIL PROTECTED]
http://www.nwaa.com
Sales and brokering of antique autos and parts.
Linux- Coming Soon To A Desktop Near You
Registered Linux User #183936
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