I'm trying to decipher:
when I select the record to edit the drop-downlist has
the first option as the value instead of what the corresponding
StateID in
the column reads. How can I correct this? The form to insert and
edit have
the below code and correctly insert the StateID
What exactly is happening? Run the script, do a View Source on the
resulting page; show us the HTML generated.
-----Original Message-----
From: Steve Fitzgerald [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, March 26, 2002 5:22 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Selecting Drop Down Value From DB to Edit
I have the below code that populates a drop down list. The code will
correctly insert the value $StateID into another a table. The problem I am
running into is that when I select the record to edit the drop-downlist has
the first option as the value instead of what the corresponding StateID in
the column reads. How can I correct this? The form to insert and edit have
the below code and correctly insert the StateID. I tried to write and if
statement to state that if the StateID were == to the StateID in he table
then print selected, but I think I am missing something.
Any suggestions?
Thanks.
<?php
// populates state drop-down list
$get_stateid_query = mysql_query("SELECT * FROM State INNER JOIN RaceResults
ON State.StateID WHERE RaceID='$RaceID'");
echo " <select name=\"StateID\">\n";
while ($myrow = mysql_fetch_array($get_stateid_query)) {
echo ' <option
value="'.$myrow["StateID"].'">'.$myrow["StateName"]."</option>\n";
}
echo " </select>\n";
?>
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