I have problems with mysql_fetch return the wrong records. If I execute the
sql statement in mysql, I receive the correct results. When I used
mysql_fetch function, it does not return the correct results. Below is my
function and the format sql statement
function companiesByBusiness_ZipCode_BusinessOrContactName( $ctgyno,
$zipcode, $businessandcontactname ) {
$sql = "select company_no, name, contact, business_phone, mobile_phone,
services_desc, brief_bio, pager, address, city, state, zipcode,
picture_file, case ifnull(picture_file, 'No Picture') when 'No Picture' then
'b' else 'a' end pic_ind from company";
if( $ctgyno != "ALL") {
$sql .= " where business_ctgy_no = $ctgyno";
if( $zipcode != "" ) {
$sql .= " and (zipcode like '".substr( $zipcode, 0, 3 )."%' and zipcode
!= '$zipcode')";
}
if( $businessandcontactname != "" ) {
$sql .= " and (name = '$businessandcontactname'";
$sql .= " or contact = '$businessandcontactname')";
}
$sql .= " order by pic_ind, name, company_no";
}
$query = mysql_query( $sql ) or die( $sql."<p>".mysql_error() );
//$numrows = mysql_num_rows( $query );
while( $assoc = mysql_fetch_assoc( $query ) ) {
$rows[] = $assoc;
sql statement:
select company_no, name, contact, business_phone, mobile_phone,
services_desc, brief_bio, pager, address, city, state, zipcode,
picture_file, case ifnull(picture_file, 'No Picture') when 'No Picture' then
'b' else 'a' end pic_ind from company where business_ctgy_no = 1 and
(zipcode like '276%' and zipcode != '27616') and (name = 'Gil Bryan' or
contact = 'Gil Bryan') order by pic_ind, name, company_no
It seems like it is ignoring the last condition, name = 'Gil Bryan' or
contact = 'Gil Bryan'). Any help is greatly appreciated.
}
return $rows;
}
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