hii
i have one form in which i print records from mysql database. while
displyaing those records i display one checkbox with each record. i want the
user should select the checkbox corresponding to the record which s/he wants
to delete.
i display those records after running one query. hence each time no.of
records are diff. so its difficult to hard code names for check boxes. for
name attribute in <input type=checkbox> tag, i define one array. having same
name as the key field in the table. and value for which is also set
dynamically.
<FORM NAME = "act_qmd_subj_frm" METHOD = "POST" ACTION =
"confirm_delete.php">
while ($row = mysql_fetch_array($result))
{
......
echo "<tr>";
//call function to display the contents of $row in table
print_entry($row,"subj_id","subj_name","subj_desc");
print " <td valign=top align=center><input type=checkbox
name=\"subj_id[]\" value=\"".$row["subj_id"]."\"> Yes, delete entry
#".$row["subj_id"]."</td>\n";
.......
}
<INPUT TYPE="submit" NAME="del_but" VALUE="Delete">    
<INPUT TYPE="submit" NAME="modify_but" VALUE="Modify">    
<INPUT TYPE="reset" NAME="clear_but" VALUE="Clear">    
</FORM>
when i submit the form to confirm_delete.php i run one code there to print
the array subj_id[] which is supposed to contain values of the checkboxes
which are selected to delete or to modify. but the array subj_id[] contains
no value at all. echo count($subj_id) gives 0.
is there any other way to pass multiple checkbox values from the form???
i got the above trick from the book "MySQL/PHP Database Applications" (By,
Jay Grrenspan and Brad Bulger) in one script they have passed checkbox value
thru array by this way, and its working fine.
can anyone PLS figure out what wrong im doing???
thnx and regds,
smita.
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