Hi,
If anyone can help me with this I'd be most appreciative.
I'm constructing 2 arrays of IDs from 2 different tables. Then I want to
compare one to the other and only use the results that both arrays share
in common to do a query loop that pulls the information for the related
IDs to display.
The error I get from the code below is:
Warning: Argument #2 to array_intersect() is not an array in
/usr/local/www/vhosts/trustbuild.co.nz/htdocs/partners_region.php on
line 185
I cant see what is causing the problem.
<<< Start of My Existing Code >>>
$result = mysql_query("SELECT partner_id FROM partner_region WHERE
region_id = '$r' ORDER BY partner_id");
if ($row = mysql_fetch_array($result)) {
do {
partner_region[] = $row['partner_id'];
} while ($row = mysql_fetch_array($result));
}
if (count($partner_region) != 0) {
array_unique($partner_region);
}
$result2 = mysql_query("SELECT id FROM partner WHERE type = '$t' ORDER
BY id");
if ($row2 = mysql_fetch_array($result2)) {
do {
partner_type[] = $row2['id'];
} while ($row2 = mysql_fetch_array($result2));
}
if (count($partner_type) != 0) {
array_unique($partner_type);
}
$partner = array_intersect($partner_region, $partner_type);
if (count($partner) != 0) {
foreach ($partner as $p) {
$result3 = mysql_query("SELECT * FROM partner WHERE id = '$p'");
if ($row3 = mysql_fetch_array($result3)) {
do {
$company_name = $row3['company_name'];
$contact_name = $row3['contact_name'];
$physical_address = $row3['physical_address'];
$postal_address = $row3['postal_address'];
$city = $row3['city'];
$phone = $row3['phone'];
$fax = $row3['fax'];
$email = $row3['email'];
$url = $row3['url'];
$gst_number = $row3['gst_number'];
$company_age = $row3['company_age'];
$services = $row3['services'];
$region = region($r);
if ($count == 0) {
echo "<tr><td bgcolor='#FFFFFF'><a href='closeup.php?id=$id'>$region
$company_name</a><br>Type: $company_type<br>Contact Name:
$contact_name<br>".nl2br($physical_address)."</td></tr>";
$count++;
} else {
echo "<tr><td bgcolor='#DDDDDD'><a
href='closeup.php?id=$id'>$region $company_name</a><br>Type:
$company_type<br>Contact Name:
$contact_name<br>".nl2br($physical_address)."</td></tr>";
$count--;
}
} while ($row3 = mysql_fetch_array($result3));
}
}
} else {
echo "There are no listings for your criteria. Please try again.<br>";
}
<<< End of My Existing Code >>>
Thanks in advance for any help with this one,
Nigel Dunn
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
