I am trying to convert something that I have working in a PHP script
to be a function in a library type of file. The code contained in the
function works fine in another script, but I am currently getting no output
from the function. I have a question about the nature of functions that may
help clear up my problems.
Do 'echo' commands within functions actually work to directly
display information? I have only used functions up to this point that use
the 'return' command to pass a variable back to the script that called the
function. I am pretty confused on how to actually use a function that
formats data to be displayed. This is my primary source of confusion.
Below is the function that is giving me trouble:
function CheckboxList($query) {
$result1 = mysql_query($query);
do {
$sys = split('-', $list['id-sys']);
if ($cnt == 1) {
$cnt = 2;
echo "<tr><td width=\"161\"><input name=\"system[]\" type=\"checkbox\"
value=\"$sys\">";
echo $sys."</td>";
} elseif ($cnt == 2) {
$cnt = 3;
echo "<tr><td width=\"161\"><input name=\"system[]\" type=\"checkbox\"
value=\"$sys\">";
echo $sys."</td>";
} elseif ($cnt == 3) {
$cnt = 4;
echo "<tr><td width=\"161\"><input name=\"system[]\" type=\"checkbox\"
value=\"$sys\">";
echo $sys."</td>";
} elseif ($cnt == 4) {
$cnt = 1;
echo "<tr><td width=\"161\"><input name=\"system[]\" type=\"checkbox\"
value=\"$sys\">";
echo $sys."</td></tr>";
}
} while ($list = mysql_fetch_assoc($result1));
}
Here is also the way I am calling this function:
<snip...>
$query = "SELECT * FROM accounts WHERE verifyurl='$safe_verify_string'";
<snip...>
CheckboxList($query);
<snip...>
Is there something wrong with the way in which I am calling this
function? Thanks in advance for all the help.
Scott Nipp
Phone: (214) 858-1289
E-mail: [EMAIL PROTECTED]
Web: http:\\ldsa.sbcld.sbc.com
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