Thanks guys.  I was able to work through this issue pretty much on
my own.  I got this portion of things working nicely except for a form
button that is appearing at the top rather than the bottom of the page.

-----Original Message-----
From: Mark [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 06, 2002 1:58 PM
To: '[EMAIL PROTECTED]'
Subject: Re: [PHP-DB] Function questions...


$sys is an array, so echoing $sys will cause problems.

Are you trying to get a 4xN table of values and checkboxes? There's
got to be an easier way...

--- "NIPP, SCOTT V (SBCSI)" <[EMAIL PROTECTED]> wrote:
>       I am trying to convert something that I have working in a PHP
> script
> to be a function in a library type of file.  The code contained in
> the
> function works fine in another script, but I am currently getting
> no output
> from the function.  I have a question about the nature of functions
> that may
> help clear up my problems.
> 
>       Do 'echo' commands within functions actually work to directly
> display information?  I have only used functions up to this point
> that use
> the 'return' command to pass a variable back to the script that
> called the
> function.  I am pretty confused on how to actually use a function
> that
> formats data to be displayed.  This is my primary source of
> confusion.
> 
>       Below is the function that is giving me trouble:
> 
> function CheckboxList($query) {
>   $result1 = mysql_query($query);
>   do {
>     $sys = split('-', $list['id-sys']);
>     if ($cnt == 1) { 
>       $cnt = 2; 
>       echo "<tr><td width=\"161\"><input name=\"system[]\"
> type=\"checkbox\"
> value=\"$sys\">";
>       echo $sys."</td>";
>     } elseif ($cnt == 2) { 
>         $cnt = 3;
>       echo "<tr><td width=\"161\"><input name=\"system[]\"
> type=\"checkbox\"
> value=\"$sys\">";
>       echo $sys."</td>";
>     } elseif ($cnt == 3) { 
>         $cnt = 4;
>       echo "<tr><td width=\"161\"><input name=\"system[]\"
> type=\"checkbox\"
> value=\"$sys\">";
>       echo $sys."</td>";
>       } elseif ($cnt == 4) { 
>         $cnt = 1;
>       echo "<tr><td width=\"161\"><input name=\"system[]\"
> type=\"checkbox\"
> value=\"$sys\">";
>       echo $sys."</td></tr>";
>       }
>   } while ($list = mysql_fetch_assoc($result1));
> }
> 
>       Here is also the way I am calling this function:
> <snip...>
> $query = "SELECT * FROM accounts WHERE
> verifyurl='$safe_verify_string'";
> <snip...>
> CheckboxList($query);
> <snip...>
> 
>       Is there something wrong with the way in which I am calling this
> function?  Thanks in advance for all the help.
> 
> 
> Scott Nipp
> Phone:  (214) 858-1289
> E-mail:  [EMAIL PROTECTED]
> Web:  http:\\ldsa.sbcld.sbc.com
> 
> 
> 
> -- 
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
> 


=====
Mark Weinstock
[EMAIL PROTECTED]
***************************************
You can't demand something as a "right" unless you are willing to fight to
death to defend everyone else's right to the same thing.
-Stolen from the now-defunct Randy's Random mailing list.
***************************************

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