Mark,
That was just about it. Once I moved the $c incrementor inside the loop it
worked perfectly.
$c = 0;
print("<tr>");
while($row = mysql_fetch_array($dbResult))
{
$c++;
print("<td>{$row['server_name']}</td>");
if(($c % 4) == 0)
{
print("</tr><tr>");
}
}
I appreciate you all helping a me (a rookie) through this problem.
Art
"Mark" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> It's not incrementing $c. Start out with $c=0;, then Add $c++; after
> the while line (not after the whole while statement).
>
> Like this:
> $c = 0;
> print("<tr>");
> while($row = mysql_fetch_array($dbResult))
> $c++;
> {
> print("<td>{$row['server_name']}</td>");
> if(($c % 4) == 0)
> {
> print("</tr><tr>");
> }
> }
>
> You'll also need a print("</tr></table>") at the end, but I assume
> you knew that...
>
> --- "Chevalier, Arthur" <[EMAIL PROTECTED]> wrote:
> > You are right about my query. I am only pulling down one column.
> >
> > As you guys can probably tell I am pretty inexperienced with this.
> > I tried
> > what you said and still got the same results.
> >
> > Here are snippets of my code and maybe this will depict what I am
> > doing
> > wrong:
> >
> > After creating the connection:
> >
> > $query = "select server_name from servers where midtier =
> > '$server'";
> > $dbResult = mysql_query($query,$dblink);
> >
> > $c = 1;
> > print("<tr>");
> > while($row = mysql_fetch_array($dbResult))
> > {
> > print("<td>{$row['server_name']}</td>");
> > if(($c % 4) == 0)
> > {
> > print("</tr><tr>");
> > }
> > }
> >
> >
> >
> > -----Original Message-----
> > From: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
> > Sent: Thursday, December 05, 2002 3:26 PM
> > To: Ryan Jameson (USA); Art Chevalier; [EMAIL PROTECTED]
> > Subject: Re: [PHP-DB] MySQL Array
> >
> > I think he meant that he is only pulling one column, i.e. "field1"
> > with each
> > mysql_fetch_array and he wants that in four columns.
> >
> > $c = 1;
> > echo "<tr>";
> > while($ar = mysql_fetch_array($result))
> > {
> > echo "<td>{$ar['field1']}</td>";
> > if(($c % 4) == 0) { echo "</tr><tr>"; }
> > }
> >
> > You'll have to account for incomplete rows and clean up the output,
> > but
> > hopefully that gives you an idea.
> >
> > ---John Holmes...
> >
> > ----- Original Message -----
> > From: "Ryan Jameson (USA)" <[EMAIL PROTECTED]>
> > To: "Art Chevalier" <[EMAIL PROTECTED]>;
> > <[EMAIL PROTECTED]>
> > Sent: Thursday, December 05, 2002 3:05 PM
> > Subject: RE: [PHP-DB] MySQL Array
> >
> >
> > while ($ar = mysql_fetch_array($rs))
> > echo "<tr><td>".
> > $ar['field1']."</td><td>".$ar['field2']."</td></tr>";
> >
> >
> > Make sense?
> >
> > -----Original Message-----
> > From: Art Chevalier [mailto:[EMAIL PROTECTED]]
> > Sent: Thursday, December 05, 2002 12:44 PM
> > To: [EMAIL PROTECTED]
> > Subject: [PHP-DB] MySQL Array
> >
> >
> > Hello,
> >
> > I am pulling one column out of a MySQL table in an array. I want
> > to place
> > each element into a HTML table 4 rows across. I am currently doing
> > this
> > with the mysql_fetch_array() function. How can I pull out 4 array
> > elements
> > in one pass through a while loop?
> >
> > Thanks
> >
> > Art Chevalier
> >
> >
> >
> > --
> > PHP Database Mailing List (http://www.php.net/)
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> >
> >
> > --
> > PHP Database Mailing List (http://www.php.net/)
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> >
>
>
> =====
> Mark Weinstock
> [EMAIL PROTECTED]
> ***************************************
> You can't demand something as a "right" unless you are willing to fight to
death to defend everyone else's right to the same thing.
> -Stolen from the now-defunct Randy's Random mailing list.
> ***************************************
>
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