I might be overlooking something, but can't you just do this?
$query = "SELECT s_id, subnet_name,subnetaddr,subnetmask,dnsdomain,
location, contact, ccn FROM subnets ORDER BY subnetaddr";
If you can't, you can sort the array like this.
<?
$query = "SELECT s_id, subnet_name,subnetaddr,subnetmask,dnsdomain,
location, contact, ccn FROM subnets";
$results = mysql_query( $query );
while ( $iptable = mysql_fetch_array( $result ) ) {
$iptable['subnetaddr'] = ip2long( $iptable['subnetaddr'] );
}
?>
You can subsequently sort the array for the desired result.
Edward Dudlik
Becoming Digital
www.becomingdigital.com
----- Original Message -----
From: "Snijders, Mark" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, 10 June, 2003 08:55
Subject: [PHP-DB] array fill/sort question
hi,
I'm working on a ipaddres/subnet programm
now i have a talbe with a lot of information about ip-addresses
i'm having this query:
SELECT s_id, subnet_name,subnetaddr,subnetmask,dnsdomain, location, contact,
ccn FROM subnets
the subnetaddr field looks like this : 100.20.20.1 and is ofcourse a
varchar field
BUT before displaying it on the screen i have to sort it by subnetaddr and
then show it
but i have to sort it as integer, so i use the php-function ip2long();
so you get a decimal...
so what i have to do:
do the query> make a decimal field of the 'subnetaddr' put it in an array,
sort it and display it
BUT how can i put ALL of the fields in the query in an array, sort it, and
then display it?
please help me, I can't work it out :(
thanks, Mark
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