Ah ha! perfect! I wanted a way for SQL to handle this. DUH!
Thanks John.
-Matt
On Thu, 2003-08-14 at 17:20, John W. Holmes wrote:
> Matt Babineau wrote:
> > Here is what I have for a layout:
> >
> > thing_id -> it is a hash value (md5())
> >
> > I have a user session variable that is an array "thing_id's that were
> > viewed".
> >
> > So each time the user click a like to view a thing_id, I note that in a
> > session variable, so when they go back to the home page, all the things
> > they have viewed are not shown, only the ones they have not viewed.
> >
> > Thing_id
> > ---------
> > 1 | hash_id_1
> > 2 | hash_id_2
> > 3 | hash_id_3
> > 4 | hash_id_4
> >
> > Viewed (Session Var)
> > --------------------
> > 1 | hash_id_2
> > 2 | hash_id_4
> >
> >
> > So when the user hits the homepage, they should get a list of 2 hash
> > ID's hash_id_1 and hash_id_3. That is how I want this to work, I just
> > need a slick way to compare and filter the viewed hash_id's from the
> > complete list I am pulling form the DB.
> >
> > Does that help?
>
> Yes. You only need to maintain one list, actually, the list of "things"
> that the user has viewed. Then, do something like this:
>
> $list = "'" . implode("','",$_SESSION['viewed_hash']) . "'";
> $query = "SELECT thing FROM Thing_Table WHERE thing_hash NOT IN ($list)";
>
> Run that query and you'll have all of the results in the table that the
> view has not seen.
>
> --
> ---John Holmes...
>
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