Tried both... Still no joy...

The statement becomes
$info = mysql_query('Select * From customer Where customer.customer LIKE St
Mary's Hospital');

Maybe I need to be a little clearer... Seem that the sql statement is now
getting the correct value
But the extra ['] is confusing it....
 

-----Original Message-----
From: ma [mailto:[EMAIL PROTECTED] 
Sent: Wednesday, November 05, 2003 2:07 PM
To: PHP-DB
Subject: Re: [PHP-DB] Select Value with 's

hi

ok - than make it this way:

$info = mysql_query( Select * From customer Where customer.customer LIKE "St
Mary's Hospital");

anyways - shouldn't it be like this?:

$FF = "St Mary's Hospital";
$info = mysql_query('Select * From customer Where customer.customer LIKE
"'.$FF.'"');

_ma

# life would be easier if i knew the source code...

> Von: "Aleks @ USA.net" <[EMAIL PROTECTED]>
> Datum: Wed, 5 Nov 2003 14:01:37 -0500
> An: "'ma'" <[EMAIL PROTECTED]>, "'PHP-DB'" <[EMAIL PROTECTED]>
> Betreff: RE: [PHP-DB] Select Value with 's
> 
> Sorry I left out the exact form....
> 
> It is
> 
> $info = mysql_query( Select * From customer Where customer.customer 
> LIKE 'St Mary's Hospital');
> 
> 
> 
> -----Original Message-----
> From: ma [mailto:[EMAIL PROTECTED]
> Sent: Wednesday, November 05, 2003 1:56 PM
> To: PHP-DB
> Subject: Re: [PHP-DB] Select Value with 's
> 
> hi
> 
> think you should use ' when you create the query and " in the 
> SQL-statement for comparison:
> 
> $qry = 'SELECT *
> FROM customer
> WHERE customer.customer LIKE "'.$FF.'"';
> 
> _ma
> 
> # life would be easier if i knew the source code...
> 
>> Von: "Aleks @ USA.net" <[EMAIL PROTECTED]>
>> Datum: Wed, 5 Nov 2003 13:52:51 -0500
>> An: "'CPT John W. Holmes'" <[EMAIL PROTECTED]>, "'ma'"
>> <[EMAIL PROTECTED]>, "'PHP-DB'" <[EMAIL PROTECTED]>
>> Betreff: RE: [PHP-DB] Select Value with 's
>> 
>> Thanks John for the answer.... But...
>> 
>> Now my select statement on the Result.php page errors out when The 
>> value has the [']in it..... What the select statement looks like now 
>> Is
>> 
>> Select *
>> From customer
>> Where customer.customer LIKE 'St Mary's Hospital'
>> 
>> Error message is
>> 
>> Warning mysql_fetch_array(): supplied argument is not a valid MySQL 
>> result
>> 
>> 
>> 
>> 
>> 
>> -----Original Message-----
>> From: CPT John W. Holmes [mailto:[EMAIL PROTECTED]
>> Sent: Wednesday, November 05, 2003 1:45 PM
>> To: Aleks @ USA.net; 'ma'; 'PHP-DB'
>> Subject: Re: [PHP-DB] Select Value with 's
>> 
>> From: "Aleks @ USA.net" <[EMAIL PROTECTED]>
>>> First I build my select list:
>>> 
>>>     <SELECT NAME="Cid" size="1">
>>>     <OPTION Selected VALUE="">All Customers</OPTION>
>>> 
>>> <?
>>>  While ($Site = mysql_fetch_array($S))  {
>>>   $Sid = $Site["CID"];
>>>   $SName = htmlspecialchars($Site["Customer"]);
>>>   echo("<option value='$SName'>$SName</options>\n");
>> 
>> Easy fix: echo("<option value=\"$SName\">$SName</options>\n");
>> 
>> Long version:
>> 
>> htmlspecialchars() does not change single quotes unless you pass 
>> ENT_QUOTES as the second parameter. What you're ending up with is a 
>> value
> such as:
>> 
>> value='St. Mary's'
>> 
>> which, HTML will interpret as a value of "St. Mary" and an unknown s'
>> attribute. So,
>> 
>> $SName = htmlspecialchars($Site["Customer"], ENT_QUOTES); 
>> echo("<option value='$SName'>$SName</options>\n");
>> 
>> will convert single quotes to HTML entities and not affect the value.
>> 
>> The "easy fix" above works because it uses double quotes around the 
>> value and htmlspecialchars() already changes double quotes by default.
>> 
>> ---John Holmes...
>> 
> 
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