What error is it giving you? What's not happening? Saying 'It doesn't work'
doesn't help much especially when you don't give all the code.
Advertising
-Micah
On Wed January 21 2004 11:10 am, mayo wrote:
> I have a table displaying data. The column headers are links that allow the
> users to order the content in ASC or DESC.
>
> basic version is:
>
> <a href="somefile.php?order=ASC">Title</a>
>
>
> a closer to reality version is (or would be if it worked)
>
> <a href="somefile.php?order=
> if ($order == "ASC"){
> echo "DESC";
> }else{
> echo "ASC";
> }
> ">
>
> (Actually that would be a switch/case :-) )
>
>
> The sql call is
>
> $selection = mysql_query("
> SELECT *
> FROM classes
> ORDER BY title $order
> ")
>
>
> And since there is no query string when someone lands on the page there
> needs to be a default value set:
>
>
> // setting the default variables
>
> if(!isset($order)){$order="ASC";}
>
> Unfortunately its not working :(
>
>
> thx, gil
>
> > -----Original Message-----
> > From: Micah Stevens [mailto:[EMAIL PROTECTED]
> > Sent: Wednesday, January 21, 2004 1:59 PM
> > To: [EMAIL PROTECTED]
> > Cc: mayo
> > Subject: Re: [PHP-DB] using query_strings in sql
> >
> >
> >
> > I may be misunderstanding you, but your first statement about
> > pulling from a
> > query string is throwing me.
> >
> > <?php echo $section; ?> will only display the value of $section
> > on the screen.
> > You will need to build a form to get a value into $section.
> >
> > <form action="soemthing.php">
> > <input type="text" name="section">
> > </form>
> >
> > something.php:
> >
> > <?php echo "This is what was submitted in the form: ".$section; ?>
> >
> > Now you can do your query:
> >
> > $selection = mysql_query("SELECT *
> > FROM classes
> > WHERE
> > classCategory = '$section'
> > ")
> >
> > you'll notice I pulled the other variables out since you had not
> > defined them
> > yet, like your ordering variables. Otherwise the SQL would end
> > with ORDER
> > which will cause an error..
> >
> > -Micah
> >
> > On Wed January 21 2004 10:41 am, mayo wrote:
> > > I'm a cold fusion refugee and am having incredible problems
> >
> > with something
> >
> > > that I think is relatively easy -- so I must be missing
> >
> > something basic.
> >
> > > I would like to pull info from a query string and use it
> >
> > inside a database
> >
> > > call.
> > >
> > > I can pull the query string into a general variable:
> > >
> > > <?php echo $section; ?>
> > >
> > > now I would like to use it in a SQL statement, or in
> > > if/else clauses to modifiy results from queries.
> > >
> > > examples below:
> > >
> > >
> > > USE query_string in SQL :
> > >
> > > <?php
> > >
> > > function whatever(){
> > >
> > > $username = "";
> > > ...
> > >
> > > // setting the default variables
> > >
> > > if(!isset($category)){$category="Something";}
> > > if(!isset($section)){$section="SomethingElse";}
> > >
> > > [EMAIL PROTECTED]($hostname,$username,$password);
> > > mysql_select_db($database);
> > > $selection = mysql_query("
> > > SELECT *
> > > FROM classes
> > > WHERE
> > > classCategory = '$category'
> > > ORDER BY $reorder $order
> > > ")
> > >
> > > ...
> > >
> > > ?>
> > >
> > > The PHP SQL call below work nicely:
> > >
> > > while ($row = mysql_fetch_array($selection)){
> > >
> > > echo $row["sectionName"];
> > >
> > > }
> > >
> > > now I would like to do an if/else to modifiy it:
> > >
> > >
> > >
> > > while ($row = mysql_fetch_array($selection)){
> > >
> > > if (section == $sectionName){
> > > echo "<b>" . $row["sectionName"] . "</b>";
> > > }else{
> > > echo $row["sectionName"];
> > > }
> > >
> > > Nothing is working. I must be missing something basic over here.
> > >
> > > thx, Gil
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