I'm still not quite there, I can see the misty shape of a solution but the details are still a bit hazy.
The code I posted it the whole shebang. I've made some attempts to 'form enable' it, but can't figure out where to put the <form.../form>, and submit stuff so the entire thing renders as a form and creates the variable you describe.
I have built a php/html form with simple single value fields but can't see how to get from there to the sql populated dropdown etc...
It would be a huge favor if you could sketch out the blocks of php and html with a text description of what goes in the blocks so I could at least get started.
Part of what I'm struggling with is that there are at least 3 ways to do everything and whenever I find examples that are close to what I need, the layout is totally different from whatever I've pasted together before or uses a different php/sql/htlm method so I wind up starting over and getting back into a corner again. Programming is worse than English!
Thank you so much for your reply. I'm going to start hacking to see if I can get something working and will check back here later.
TIA
Doug
John W. Holmes wrote:
From: "Doug F" <[EMAIL PROTECTED]>
Populate a dropdown list with values from a MySQL db (done and working). Use the selected value as the 'where' clause in a second query. Return the results and display them to the user.
Any pointers are appreciated - noob^3 (html, mysql, and php).
Doug
Code that I'm using:
<html> <body> <?php
// connect to db $db = mysql_connect("localhost"); mysql_select_db("test",$db);
// build query $sitequery = "SELECT site from sitedata order by site";
// generate result set $siteresult = mysql_query($sitequery);
// use results echo "Select a site from the list below: <br><br><select name='site'>"; while($siterow = mysql_fetch_array($siteresult)) echo "<option value='".$siterow["site"]."'>" $siterow["site"]."</option>"; echo "</select></td>";
When the form is submitted, the value chosen will be in $_REQUEST['site'] (or $_GET['site'] or $_POST['site'], depending upon your form method).
Then just create your query:
$query = "SELECT * FROM sitedata WHERE site = '{$_REQUEST['site']}'";
If magic_quotes_gpc is not ON, then you'll want to run mysql_escape_string() on the value first.
$site = mysql_escape_string($_REQUEST['site']); $query = "SELECT * FROM sitedata WHERE site = '$site'";
See the recent threads on SQL Injection for a reason why. :)
---John Holmes...
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