Of course you can
$whatever_db_linkid = mysql_connect($connectiondetails_for_whatever_db);
if(is_resource($whatever_db_linkid)) { mysql_select_db('whatever_db',
$whatever_db_linkid); }
$someother_db_linkid = mysql_connect($connectiondetails_for_someother_db);
if(is_resource($someother_db_linkid)) { mysql_select_db('someother_db',
$someother_db_linkid); }
// work your magic..
mysql_close($whatever_db_linkid);
mysql_close($someother_db_linkid);
-----Original Message-----
From: Gary Rachel [mailto:[EMAIL PROTECTED]
Sent: den 5 oktober 2004 04:31
To: [EMAIL PROTECTED]
Subject: [PHP-DB] accessing two databases within one script
I have a page where I need to access two different databases in mysql.
After accessing the first database I used mysql_close($connection);
and then code to access the other database. The first database access
works fine, the second gives me the following error message:
*Warning*: mysql_query(): Can't connect to local MySQL server through
socket '/tmp/mysql.sock'
I've tried not using the mysql_close statement. But that option doesn't
select the new database, it seems to stay connected to the previous one,
despite my specifying a new database to access. Can I not access two
databases within the same script?
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