That's probably the best way to go, but if you wanted another way:
$mySqlDate = "20041008";
$month = substr($mySqlDate,4,2);
$day = substr($mySqlDate,6,2);
$year = substr($mySqlDate,0,4);
$mySqlDateSerial = mktime(0,0,0,$month,$day,$year);
$twoWeeksAgoSerial = mktime(0,0,0,date("m"),date("d")-14,date("Y"));
If ($mySqlDateSerial < $twoWeeksAgoSerial) {
echo "<h5>Assignment In Void:</h5><br><h4>Assignments in the void are
read-only";
require('footer.php');
exit;
}
But I always do things the hard way. Haha.
-TG
> -----Original Message-----
> From: Wendell Frohwein [mailto:[EMAIL PROTECTED]
> Sent: Friday, October 08, 2004 2:57 PM
> To: 'Cole S. Ashcraft'; [EMAIL PROTECTED]
> Subject: RE: [PHP-DB] -14 Days Ago
>
>
> You can trying using the MySQL DATE_ADD() , DATE_SUB , and NOW()
> functions.
>
>
> -wendell frohwein
>
> -----Original Message-----
> From: Cole S. Ashcraft [mailto:[EMAIL PROTECTED]
> Sent: Friday, October 08, 2004 11:36 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] -14 Days Ago
>
> I am trying to see whether a data in an array pulled from a MySQL DB
> (YEARMONTHDATE) is older than 14 days ago. I am trying to do this in
> PHP. My code looks like:
>
> if($array['due'] <= $today - 14)
> {
> echo "<h5>Assignment In Void:</h5><br><h4>Assignments in the void are
> read-only";
> require('footer.php');
> exit;
> }.
>
> I am having problems with the math. How do I do a date subtraction
> without ending up with something like 20040994 (not a valid date)?
>
> Thanks,
> Cole
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
